Correct Answer - D
A is not correct but R is correct.
Hybridisation can be determined by counting `sigma-`bond
`{:(" "3 sigma " " 2 sigma " " 3 sigma),(H_(2)C = C = CH_(2)),(3 sigma - sp^(2) " hybridisation "),(2 sigma - sp " hybridisation "):}`
Correct assertion. In `H_(2) = C = CH_(2)`, the central carbon is sp-hybridised whereas the terminal carbons are `sp^(2)` -hybridised.