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`XY_(2)` dissociates `XY_(2)(g) hArr XY(g)+Y(g)`. When the initial pressure of `XY_(2)` is `600` mm Hg, the total equilibrium pressure is `800` mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.
A. 50
B. 100
C. 166.6
D. 400

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Correct Answer - B
`{:(,XY_(2),hArr ,XY,+,Y),("Initial pressure",600,,0,,0):}`
p is fall in pressure due to dissociation of `XY_(2)` Eq. pressure `600-p" "p" "p`
or `600-p+p+p=800`
or `p=800-600=200`
`:. K=(200xx200)/(400)=100`

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