Question

Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative ?
A. `CH_(3) - CH_(2) - .^(**)CH_(2) - CH_(5)`
B. `CH_(3) - .^(**)CH = CH - CH_(3)`
C. `CH_(3) - CH_(2) - C -= .^(**)CH`
D. `CH_(3) - CH_(2) - CH = .^(**)CH_(2)`

Answer 1

Correct Answer - C
Electrongativity of carbon atom depends on their state of hybridisation. More s-character more the electronegativity.
`{:(sp^(3),lt,sp^(2),lt,sp,),(25% s,,33% s,,50% s,):}`
Thus, sp-carbon has the highest electronegativity, i.e., option (c) `(CH_(3) - CH_(2) - C -= .^(**)CH)` is correct