Correct Answer - D
`rho_w=0.8gm/cc`
=density of wood
`rho_(pb)=11.3gm/cc`
=density of lead
`m_w=200g`
`=mass of good
`Here (m_2m_(pb))g=(V_w+V_(pb))rhoxxg`
[where rho=density of water]
`rarr (m_w+m_(pb))=(m_2/rho_w+m_(pb)/rho_(pb))rho`
`rarr (200+m_(pb))=(200/0.8+m_(pb)/11.3)xx1`
`-m_(pb)-m_(pb)/11.3 =250-200`
`rarr (10.3_(pb)/11.3=50`
`-. m_(pb)=(50xx11.3)/10.3=54.8gm