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A police is chasing a culprit going n a motorbike. The motorbike crosses a turning at a speed of 72 km/h.
The jeep follows it at a speed of 90 km/h, crossing the turning tenseconds latert than the bike. Assuming that they tavel at constant speeds, how far from the turning will the jeep catch up with the bike?

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Best answer
Correct Answer - A::B::C::D
`V_p=0` km/h=25 m/s
`V_e`= 72 km/h=20 m/s
In 10 sec culprit reaches at point B from A. Distance covered by culprit
`S=vt=20xx10=200m` At time t=10 sec
the police jeepis 200 m behind the Culprit.
Relative velocity between jeep and culprit
`25-20`=`5m/s`
Time =S/v= 200/5=40s (Relative velocity is considered).`
In 40 s the police jeep will move from A to a distance S
where `
S=vt=25xx40
= 1000 m = 1.0 km` away
`:.` The jeep will catch up with the bike, 1 km far from the turning.

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