Correct Answer - C::D
Let the initial velocity of the block be `v_(0)` due to the impact. Also the retardation of the blocks is `mug`, where `mu` is the cofficient of friction between block and surface,
(i) `v=(v_(0))+(-mug)t` (ii) `s=v_(0)t+(1)/(2)(-mug)t^(2)`
(iii) `v^(2)=v_(0)^(2)+2(-mug)s rArrv^(2)=- 2mug(s-(v_(0)^(2))/(2mug))`