Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.7k views
in Physics by (90.5k points)
closed by
Figure shows a semi-cylindrical massless gate pivoted at the point `O` holding a stationary liquid of density `rho`. The length of the cylinder is `l`. Calculate, the horizontal force exerted by the liquid on the gate.
image

1 Answer

0 votes
by (85.7k points)
selected by
 
Best answer
The force exerted by liquid on the gate is
`f_(H)=P_(av)xx`vertical projection area of the gate
`=((P_(A)-P_(B))/2)xx(2Rl)`
`=((Rrhog+3Rrhog)/2)xx2Rl=4rhogR^(2)l`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...