Correct Answer - B
On pouring oil on the left side water sides by `25 cm` from its previous level in the right limb of `U`-tube, creating a difference of levels of water by `50 cm`. Let `h cm` be the height of oil above level `A` in the left limb of `U`-tube. Equating pressures at `A` and `B` we get `P_(A)=P_(B)`
`implieshxxrho_("oil")xxg=50rho_("water")xxg`
`impliesh=(50xxrho_("water"))/rho_("oil")=(50xx1)/0.8=62.5cm`
Difference of level of oil `C` and water `D` in the two limbs
`=62.5-50=12.5cm`