Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.1k views
in Physics by (90.5k points)
closed by
A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at the sides. If the radius of the vessel is `r` and the speed of revolution is `n` rotations/second, find the difference in height of the liquid at the centre of vessel and its sides.
A. `h=(2pi^(2)n^(2)r^(2))/g`
B. `h=(4pi^(2)n^(2)r^(2))/g`
C. `h=(pi^(2)r^(2)n^(2))/g`
D. `h=(pi^(2)r^(2)n^(2))/g`

1 Answer

0 votes
by (85.7k points)
selected by
 
Best answer
Correct Answer - A
When the cylindrical vessel rotats the velocity at the sides is higher. Hence pressure at the sides is lower.
image
Equation of sruface liquid is `y=(omega^(2)x^(2))/(2g)`
Here `omega=2pin`
`x=R`
`y=h`
`h=((2pin)^(2)(R^(2)))/(2g)=(2pi^(2)n^(2)r^(2))/g`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...