Question

A liquid flows through a horizontal tube. The velocities of the liquid in the two sections, which have areas of cross section `A_(1)` and `A_(2)` are `v_(1)` and `v_(2)` respectively. The difference in the levels of the liquid in the two vertical tubes is `h`. Then

A. the volume of the liquid flowing through the tube in unit time is `A_(1)v_(1)`
B. `v_(2)-v_(1)=sqrt(2gh)`
C. `v_(2)^(2)-v_(1)^(2)=2gh`
D. the energy per unit mass of the liquid is the same in both sections of the tube

Answer 1

Correct Answer - A::C::D
`(P_(1))/(rho)+(v_(1)^(2))/2=(P_(2))/(rho)+(v_(2)^(2))/2`
`P_(1)-P_(2)=(rho)/2(v_(2)^(2)-v_(1)^(2))`
But
`P_(1)-P_(2)=rhogh=(rho)/2(v_(2)^(2)-v_(1)^(2))`
or `v_(2)^(2)-v_(1)^(2)=2gh`