Question

A body of mass `200g` tied to one end of string is revolved in a horizontal circle of radius `50cm` with angular speed `60` revolution per minute `("rpm")` on a smooth horizontal surface. Find (a) linear speed, (b) the acceleration and ( c) tension in the sting. what will happen if string is broken? (Take `pi^(2)=10)`

Answer 1

`omega=(2piN)/(60),N:rpm`
`=(2pixx60)/(60)=2pirad//s=6.28rad//s`
(a) `v=romega=0.5xx2pi=pim//s=3.14m//s`
(b) `a_(c)=(v^(2))/(r )=((pi)^(2))/(0.5)=(10)/(0.5)=20m//s^(2)`
`T=(mv^(2))/(r )=0.2xx20=2N`
When the sring is broken, tension (i.e., centripetal force) vanishes and body moves along the tangent in a straight line with speed `3.14m//s`.