Correct Answer - B
Suppose weight of gold in air = x g
weight of silver in air = `y g`
Density of gold = `d_(1)`
Density of silver = d_(2) (where d_(1) gt d_(2)`)
Volume of gold = (x)/(d_1), volume of silver = `(y)/(d_2)`
As weight of gold in water = weigth of silver in water
`(x-(x)/(d_1)xx1) g = (y-(x)/(d_2)xx1)g`
`=x/y = ((1-(1)/(d_2)))/((1-(1)/(d_1))) lt 1 or x lt y or y gt x`
i.e., weight of silver in air is more than that of gold in air.