Question

A `1kg` stone at the end of `1m` long string is whirled in a vertical circle at a constant speed of `4m//s`. The tension in the string is `6N`, when the stone is at `(g=10m//s^(2))`
A. top of the circle
B. bottom of the circle
C. half way down
D. none of the above

Answer 1

Correct Answer - A
`(mv^(2))/(L)=(1xx(4)^(2))/(1)=16N`
`Tlt(mv^(2))/(L)`
At the highest point:
`T+mg=(mv^(2))/(L)`
`6+1xx10=16=(mv^(2))/(L)`