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In a triangle ABC AB : AC = 5 : 2, BC =9 cm. BA is produced to D, and the bisector of the Angle CAD meets BC produced at E

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In a triangle ABC AB : AC = 5 : 2, BC =9 cm. BA is produced to D, and the bisector of the Angle CAD meets BC produced at E. What is the length (in cm) of CE?
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1 Answer

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by (20 points)
Answer will be 6.

According to external angle bisector theorem.

AB/AC=BE/CE

SO, 5/2=(9+CE)/CE

by solving this equation

CE=6 .         (ans)
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