Question

A stone is thrown horizontally with a velocity of `10m//sec`. Find the radius of curvature of it’s trajectory at the end of `3 s` after motion began. `(g=10m//s^(2))`
A. `10sqrt10m`
B. `100sqrt10m`
C. `sqrt10m`
D. `100 m`

Answer 1

Correct Answer - A
Radius of curvature `r=v_(t)^(2)/(g sin alpha)`
`V=sqrt(v_(x)^(2)+v_(y)^(2))=10sqrt10`
`tan alpha=v_(x)/v_(y)=1/3, sin alpha=1/sqrt10`