Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.6k views
in Physics by (67.7k points)
closed by
In the figure shown a lift goes downwards with a constant retardation. An observer in the lift observers a conical pendulam in the lift, revolving in a horizontal circle with time period 2 seconds. The distance between the centre of the circle and the point of suspension is 2.0 m. the retardation of the lift in `m//s^(2)` is
image
A. `10 m//s^(2)`
B. `20 m//s^(2)`
C. `30 m//s^(2)`
D. `40 m//s^(2)`

1 Answer

+1 vote
by (75.2k points)
selected by
 
Best answer
Correct Answer - A
`T=2pisqrt((l cos theta)/(g_(eff)))=2pisqrt(h/(g_(eff)))`
`g_(eff)=g+a`, put T=2 ` rArr a=10 m//s^(2)` Retardation `10 m//s^(2)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...