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A tank containing gasoline is sealed and the gasoline is under pressure `P_(0)` as shown in the figure. The stored gasoline hs a density of `660 kg m^(-3)`. A sniper fires a rifle bullet into the gasoline tank, making a small hole `53 m` below the surface of gasoline. The total height of gasoline is `73 m` from the base. The jet of gasoline shooting out of the hole strikes the ground at a distance of `80 m` from the tank initially. If the pressure above the gasonline surface is `(1.39)alpha xx 10^(5)N//m^(2)` than `alpha` is- (The local atmospheric pressure is `10^(5)Nm^(-2)`)
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Correct Answer - 2
`vt = 80 m ……(i)`
`t = sqrt((2h)/(g)) = sqrt((2 xx 20)/(10)) = 2` second ……`(ii)`
from `(i)` and `(ii)` equ.
`v = 40 m//s. ……(iii)`
`P_(0) + rhogh = P_(atm) + (1)/(2) rhov_(2) …...(iv)`
on solving `(iv)` equation
`P_(0) = 2.78 xx 10^(5) Nm^(-2) = (1.39)alpha xx 10^(5)`
`alpha = 2` Ans.

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