Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.6k views
in Physics by (67.7k points)
closed by
A car is taking turn on a circular path of radius R. If the coefficient of friction between the tyres and road is `mu`, the maximum velocity for no slipping is
A. `muRg`
B. `2muRg`
C. `(muRg)^(1//2)`
D. `(2muRg)^(1//2)`

1 Answer

0 votes
by (75.2k points)
selected by
 
Best answer
Correct Answer - C
`(mv^(2))/(R)lemumgrArrv_("max")=sqrt(muRg)`
`v_("max")` : maximum velocity for no slipping

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...