Correct Answer - C
Given, `f=2400"rpm"=(2400)/(60)=40Hz`
`therefore" " omega=2pif=80pi"rad s"^(-2)`
Now, `theta=[(omega_(0)+omega)/(2)]t`
`rArr" theta=[(80pi+0)/(2)]xx10=400pirad`
`therefore` Fan will turn angle `400pi` after it is swtiched off `rArr` The number of rotation `=(theta)/(2pi)=(400pi)/(2pi)=200`