A container has a small hole at its bottom. Area of cross-section of the hole is `A_(1)` and that of the container is `A_(2)`. Liquid is poured in the container at a constant rate ` Q m^(3)s^(-1)`. The maximum level of liquid in the container will be
A. `(Q^(2))/(2gA_(1)A_(2))`
B. `(Q^(2))/(2gA_(1)^(2))`
C. `(Q)/(2g A_(1)A_(2))`
D. `(Q^(2))/(2g A_(2_^(2))`