Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
201 views
in Physics by (67.7k points)
closed by
A uniform disc of radius R is put over another unifrom disc of radius 2R of the same thickness and density. The peripheries of the two discs touch each other. Locate the centre of mass of the system.

1 Answer

0 votes
by (75.2k points)
selected by
 
Best answer
Let the centre of the bigge disc be the origin.
`2R=Radius of bigger disc
R= Radius of smaller disc `
`m_1=muRxTxxrho`
`m_2=mu(2R)^2xxTxxrho`
image
`where T=Thickness of the two discs
`rho=Density of the two discs`
`:.` Position of the centre of mass
`((m_1x_1+m_2x_2)/(m_1+m_2),(m_1y_1+m_2y_2)/(m_1+m_2))`
`x_1=R,y_1=0`
`x_2=0, y_2=0`
`((piR^2TrhoR+0)/(muR^2TrhoR+mu(2R)^2Trho),0/(m_1+m_2))`
`((piR^2TrhoR)/(5muR^2Trho))=(R/4,0)`
At `R/5` from the centre of bigger disc towards.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...