Question

A steel plate of face area 4 cm2 and thickness 0.5 cm is fixed rigidly at the lower surface. A tangential force of 10 N is applied on the upper surface. Find the lateral displacement of the upper surface with respect to the lower surface. Rigidity modulus of steel `=8.4xx10^10Nm^-2`.

Answer 1

Correct Answer - A
`A=4xx10^-4m^2`
Thickness`=0.5xx10^(-4s)m`
`F=10N`
`m=(F/(Atheta))=(10/(4x10^4theta))`
`rarr theta=10/(4xx10^-4xx8.4xx10^10)`
`=0.297xx10^-6`
lateral displacement`=theta.d`
`=(0.2970xx10^-6xx(0.5)x10^-2)`
`=1.5xx10^9m`