Question

A uniform metre stick of mass 200 g is suspended from the ceiling through two vertical strings of equal lengths fixed at the ends. A small object of mass 20 g is placed on the stick at a distance of 70 cm fomd the left end. Find the tensions in the two strings.

Answer 1

Correct Answer - A::B::D
According to the questions `m_1=200g, l=1m,m_2=20g`
Therefore
`(T_1xxr_1)-(T_2xxr_2)-(m_1gxxr_3)=0`
`rarr T_1xx0.7-T_2xx0.3-2xx0.2xxg=0`
`rarr 7T_1-3T_2=3.92` .....1
T_1+T_2=2xx9.8+0.02xx9.8`
`1.96+0.196=2.156`

`3T_1+3T_2=6.468`..........2
Adding 1 and 2 we get
`rarr 10T_1=10.3`
`rarr T_1=1.038N=1.04N`
Therefore `T_2=2.156-1.038`
`=1.18~=1.12N`