Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
81 views
in Physics by (67.7k points)
closed by
A wheel of moment of inertia `0.500 kg-m^2` and radius 20.0 cm is rotating about its axis at an angular speed of 20.0 rad/s. It picks up a stationary particle of mass 200 g at its edge. Find the new angular speed of the wheel.

1 Answer

0 votes
by (75.2k points)
selected by
 
Best answer
Correct Answer - A::D
A whel has `I=0.500 kg-m^2,r=0.2m`
`omega=20rad/s`
statioN/Ary particle =0.2 kg
Therefore `I_1omega_1=I_1omega_2`
[since exterN/Al torque =0]
`rarr 0.5x20=90.5+0.2xx0.22)omega_2`
`rarr omega_2=10/0.508`
`=19.69=19.7rad/s`
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...