Question

Two sound waves move in the same direction in the same medium. The pressure amplitudes of the waves are equal but the wavelength of the first wave is double the second. Let the average power transmitted across a cross-section by the first wave be `P_(1)` and that by the second wave be `P_(2)`. Then
A. `P_(1) = P_(2)`
B. `P_(1) = 4P_(2)`
C. `P_(2) = 2P_(1)`
D. `P_(2) = 4P_(1)`

Answer 1

Correct Answer - A
`I=p_(0)^(2)/(2 rho v)`
`p=I S, " "S`: area of x-section
`rho, v`: constant of medium
`P_(1)=P_(2)`