Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
720 views
in Physics by (90.5k points)
closed by
(iv) A closed organ pipe of length 83.2 cm and 6 cm diameter is vibrated. The velocity of sound is 340 m/s. find the number of overtones in this tube having frequency below 1000 Hz ?
A. 2
B. 4
C. 1
D. 3

1 Answer

0 votes
by (85.7k points)
selected by
 
Best answer
Correct Answer - B
Effective length 83.2+0.3 d=85 cm
`n=V/(4l) =340/(4xx0.85)=100` (fundamental frequency) other resonating frequency below 1000 Hz 100,300,500,700,900 so four overtone below 1000 Hz.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...