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The gravitational field in a region is given by `vecE = (3hati- 4hatj) N kg^(-1)`. Find out the work done (in joule) in displacing a particle by `1 m` along the line `4y = 3x + 9`.

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Correct Answer - zero
Slope of the displacement vector `m_(1)=3/4`
slope of the force vector `m_(2)=4/3`
image
`m_(1)xxm_(2)=3/4xx-4/3=-1`
i.e., force and displacement directions are perpendicular. The work doen is zero.

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