Correct Answer - B
`f_("before crossing") = f_(0)((c)/(c - v_(S))) = 1000((320)/(320 - 20))`
`f_("after crossing") = f_(0)((c)/(c + v_(S))) = 1000((320)/(320 + 20))`
`Deltaf = f_(0)"((2cv_(S))/(c^(2) - v_(S)^(2))) , (Deltaf)/(f) xx 100% = (2 xx 320 xx 20)/(300 xx 340) xx 100 = 12.54% approx 12%`