Correct Answer - B
Since the mass and radius of two stars are same, point `P` at which gravitational force will be equal, will be at equal distance (say `r`) from centre of each star. The particle should be projected to cross `P`, beyond which the particle will be attracted towards the other star.
`KE=PE` of body at `P` -PE at surface of the star
`(K_(1)GMm)/a=[-(GMm)/r-(GMm)/r]-[-K_(2) (GMm)/a]`
On solving, `r=(2a)/((K_(2)-K_(1)))2r=(4a)/((K_(2)-K_(1)))`