1000 cal of heat raises the temperature of the substance from `0^@` C to `80^@` C.
`1000=m(1000xx0.5)xx80`
(`because` specific heat`=`relative sp. Heat`xx`of water)
or `m=0.025kg`
Latent heat `=200xx5=1000cal` (`because` 1 div reads 200cal) `=0.025xxL`
`L=40000 cal//kg`
In the liquid state teperature rises from `80^@`C to `120^@` C, that is by `40^@` C after absorbing 600 cal.
`0.025Sxx40=600` or `S=600cal//kg//K`