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A glass flask whose volume is exactly 1000`cm^3` at `0^@C` is filled level full of mercury at this temperature. When the flask and mercury are heated to `100^@C`, `15.2cm^3` of mercury overflows. The coefficient of cubical expansion of Hg is `1.82xx10^(-4)//^@ C`. Compute the coefficient of linear expansion of glass.

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As `15.2cm^3` of Hg overflows at `100^@`C
(final volume of Hg)`-`(final volume off glass flask)`=15.2cm^3`
`implies1000(1+gamma_(l) theta)-1000(1+gamma_(g) theta)=15.2`,
where `theta=` rise in temperature `=100-0=100^@C`
`implies gamma_g=gamma_i-(15.2)/(1000theta)=-.000182-0.000152`
`implies gamma_g =3 xx 10^(-5)//^@C implies alpha=(gamma_g)/(3)=1xx10^(-5)//C`

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