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The height a which the weight of a body becomes `1//16th` its weight on the surface of earth (radius `R`) is

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The height a which the weight of a body becomes `1//16th` its weight on the surface of earth (radius `R`) is
A. `4R`
B. `5R`
C. `15R`
D. `3R`
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Correct Answer - D
`g/16=g/((1+h/R)^(2))`
`implies (1+h/R)=4implies h=3R`
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