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A planet in a distant solar systyem is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is `11kms^(-1)`, the escape velocity from the surface of the planet would be
A. `0.11 km//sec`
B. `1.1 km//sec`
C. `11 km//s`
D. `110 km//sec`

1 Answer

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by (67.7k points)
 
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Correct Answer - 4
`V=sqrt((2GM)/R)=sqrt((2GM_(e)xx10)/((R_(e))/10))=10sqrt((2GM_(e))/(R_(e)))=110 km//s`

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