Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
465 views
in Physics by (85.7k points)
closed
A glass vessel is filled up to 3/5th of its volume by mercury. If the volume expansivities of glass and mercury be `9xx 10^(-6)//^(@)C` and `18xx10^(-5)//^(@)C` respectively, then the coefficient of apparent expansion of mercury is
A. `17.1xx10^(-5)//^(@)C`
B. `9.9xx10^(-5)//^(@)C`
C. `17.46xx10^(-5)//^(@)C`
D. `16.5xx10^(-5)//^(@)C`

1 Answer

0 votes
by (90.5k points)
 
Best answer
Correct Answer - D
Let V be the volume of the glass vessel. Then volume of mercury will be `(3//(5)` V.
Expansion of mercury`=(3//5)Vxxgamma_mDeltaT`
And that of glass`=Vgamma_gDeltaT`
Net (effective or apparent) expansion of mercury
`DeltaV=V((3gamma_m)/(5)-gamma_g)DeltaT`
`:.` Coefficient of apparent expansion will be
`(DeltaV)/((3//5)VxxDeltaT)=((3)/(5)gamma_mgamma_g)(5)/(3)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...