Question

A sphere of alumininum of mass 0.047 kg placed for sufficient time in a vessel containing boling water, so that the sphere is at `100^(@)C`. It is then immediately transferred to 0.14 kg copper calorimeter containing 0.25 kg of water at `20^(@) C` . The temperature of water rises and attains a steady state at `23^(@)C` . calculate the specific heat capacity of aluminum. Specific heat capacity of copper = `0.386 xx 10^(3) J kg^(-1) K^(-1)`.
Specific heat capacity of water = `4.18 xx 10^(-3) J kg^(-1) K^(-1)`

Answer 1

Heat lost by aluminimum sphere = (heat gained by water) + (heat gained by calorimeter)
`0.047 xx S_(Al) xx(100^@ -2 3^@) = 0.25 xx 4180(23^@-20^@)+ 0.14 xx 386(23^@-20^@)`
`:. S_(Al) = 911 J//Kg -K`.