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+1 vote
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in Physics by (85.7k points)
closed
The final temperature, when `10 g` of steam at `100^@ C` is passed into an ice block of mass `100 g`
`(L_(steam) = 540 cal//g, L_(ice) = 80 cal//g , S_(water) =1 cal//g^(@) C)` is
A. `0^@C`
B. `15.7^@C`
C. `16.9^@C`
D. `4^@ C`

1 Answer

+1 vote
by (90.5k points)
 
Best answer
Correct Answer - A
Heat lost by steam = Heat gained by ice
`m_(steam) xx L_(v) + m_(steam) S_(w)(100^@ -theta^@) = m_(ice) L_(f) +m_(ice) S_(w) (theta^@ -0)`.

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