Question

The escape velocity of a body from the earth is `11.2 km//s`. If a body is projected with a velocity twice its escape velocity, then the velocity of the body at infinity is (in `km//s`)
A. `19.4`
B. `194`
C. `1.94`
D. `0.194`

Answer 1

Correct Answer - A
Velocity at infinity
`v_(oo)=sqrt(v^(2)-v_(e)^(2))=sqrt([2(11.2)]^(2)-(11.2)^(2))`