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`5 gm` of steam at `100^@ C` is passed into calorimeter containing liquid. Temperature of liquid rises from `32^@ C` to `40^@ C`. Then water equivalen

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`5 gm` of steam at `100^@ C` is passed into calorimeter containing liquid. Temperature of liquid rises from `32^@ C` to `40^@ C`. Then water equivalent of calorimeter and contents is
A. 40 g
B. 375 g
C. 300 g
D. 160 g
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1 Answer

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Correct Answer - B
Heat lost by steam = Heat gained by the calorimeter and contents.
`m_(steam) xx L_(v)+m_(s) xx1(100^@-40^@)=mS(40^@-32^@)`.
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