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in Physics by (85.7k points)
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A different of temperature of `25^(@)C` is equivalent to a difference of
A. `45^(@)F`
B. `72^(@)F`
C. `32^(@)F`
D. `25^(@)F`

1 Answer

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by (90.5k points)
 
Best answer
Correct Answer - A
`(C-0)/100=(F-32)/(180^(@))`
`(DeltaC)/(100^(@))=(DeltaF)/(180^(@))`
`25/(100^(@))xx180^(@)=DeltaF rArr DeltaF=45^(@)F`

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