Correct Answer - A::B::C::D
In path ACB,
W=`W_(AB)=(1)/2xx(10+30)xx10^3xx15xx10^-6`
` =0*45 J
In path AB,`
`W_(AB)(1)/2xx(10+30)xx10^3xx10^3xx15xx10^-6`
`=`(1)/(2)xx40xx15xx10^-3=0*30J`
In path ADB,`
`In path ADB,`
`W=W_(AD)+W_(DB`
`=10xx10^3(25-10)xx10^-6+0ltbrge10xx15xx10^-3=0*15J
