Question

Carnot engine takes one thousand kilo calories of heat from a reseervoir at `827^@C` and exhausts it to a sink at `27^@C`. How, much work does it perform? What is the efficiency of the engine?

Answer 1

Correct Answer - B
Given, `Q_1=10^6cal`
`T_1(827+273)=1100K`
and `T_2=(27+273)=300K`
as, `Q_2/Q_1=T_2/T_1impliesQ_2=T_2/T_1*Q_1=(300/1100)(10^6)`
`=2.72xx10^5 cal`
`W=Q_1-Q_2=7.28xx10^5cal`
Efficiency of the cycle,
`eta=(1-T_2/T_1)xx100` or `eta=(1-300/1100)xx100`
`=72.72%`