Correct Answer - A
`eta=(W_(n et))/(sumQ_(+ve))xx100`
`W_(n et)`=Area under the cycle
`=(p_0V_0)/(2)`
`sumQ_(+ve)=Q_(ABC)`
`=W_(ABC)+DeltaU_(ABC)`
=(Area under ABC)+`nC_(V) DeltaT`
`=(5/4p_(0)V_(0))+n(3/2R)(T_C-T_A)`
`5/4p_(0)V_(0)+3/2(p_CV_C-p_AV_A)`
`=5/4p_0V_0+3/2((3p_0V_0)/(2)-(p_0V_0)/(2))`
`11/4p_0V_0`
`:.` `eta=((p_0V_0//2))/((11p_0V_0//4))xx100=18.18%`