Correct Answer - B::D
(a)
`W_(n et)=Q_(n et)` in a cycle.
Since, `Q_(n et)` is negative (flows out of the gas). Hence, `W_(n et)` should aslo be negative. Or, cycle should be anti-clockwise as shown in figure.
From a to b
p=constant
`:.` `VpropT`
T has become 1.5 times. Therefore, V will also become 1.5 times.
From c to a
`p propV`
V has become `1/1.5` times. Therefore,
p will become `1/1.5` times.
In a cycle
`|Q_(n et)|=|W_(n et)|`=Area of cycle
`:.` `800=1/2(0.5p_0)(0.5V_0)`
`:.` `p_0V_0=6400J`
`W_(ca)=-Area under the graph
`=-1/2(2.5p_0)(0.5V_0)`
`=-0.625p_0V_0`
`=-0.625xx6400=-4000J`