Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
119 views
in Physics by (85.7k points)
closed
An ideal gas at `27^(@)C` is compressed adiabatically to `8//27` of its original volume. If `gamma = 5//3`, then the rise in temperature is
A. `450^@C`
B. `375^@C`
C. `225^@C`
D. `405^@C`

1 Answer

0 votes
by (90.5k points)
 
Best answer
Correct Answer - B
`T_1=27+273=300K,V_1=V,V_2=(8)/(27)V,T_2=?`
`T_1V_1^(gamma-1)=T_2V_2^(gamma-1)`
`T_2=T_1((V_1)/(V_2))^(gamma-1)=(300)((V)/((8)/(27)V))^((5)/(3)-1)=(300)((27)/(8))^((2)/(3))`
`=(300)[((3)/(2))^3]^((2)/(3))=(300)((3)/(2))^2`
`=300xx(9)/(4)=675K`
`DeltaT=T_2-T_1=675-300=375K=375^@C`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...