Question

A particle is projected with a velocity of `20 ms^(-1)` at an angle of `60^(@)` to the horizontal. The particle hits the horizontal plane again during its journey. What will be the time of impact ?
A. `3.53 s`
B. `2.4s`
C. `1.7s`
D. 1s

Answer 1

Correct Answer - A
The particle hits the horizontal plane again at time.
`T = (2u sin theta)/(g) = (40 xx sin 60^(@))/(9.8) = 3.53s`