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A cricket ball of mass 150 kg is moving with a velocity of `12 m//s` and is hit by a bat so that ball is turned back with a velocity of `20 m//s` . The force of the blow acts for 0.01 s on the ball . Find the average force exerted by the bat on the ball.

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Here ,` m = 150 g = 0.15 kg = 0.15 kg `
` u =12 m//s, upsilon = -20 m//s , t =0.01 s , F = ? `
As `Fxx 1` = impulse = change in momentum
` F xx 0.01 = m (upsilon - u) = 0.150 (-20 - 12) `
` F = (-0.150 xx 32 )/(0.01)= - 480 N ` .

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