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A body of weight `200N` is suspended with the help of strings as show in Find the tensions in the strings
image .

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Correct Answer - `T_(1) = 146.4 N; T_(2) = 179.3 N` .
Equating the horizontal components of tensions:
`T_(1) cos 30^(@) = T_(2) cos 45^(@)`
Vertical components balance the wt
`T_(1) sin 30^(@) + T_(2) sin 45^(@) = 200`
Solve to get `T_(1) = 146.4 N, T_(2) = 179.3 N` .

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