Correct Answer - b
Here, `m = 5kg , vec(F) = (-3hati + 4hatj)N`
Initial velocity at `t=0, vec(u) = (6hati -12hatj)m//s` retardation `hat a = vec(F)/(m) = ((-3hati)/(5) + (4hatj)/(5))m//s^(2)`
As final velocity is along Y-axis only , its x-component must be zero
From `upsilon = u +` at , for X component only `0 =6 hati - (3hati)/(5)t `
`t = (5 xx 6)/(3) =10s` .