Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
297 views
in Physics by (75.2k points)
Two masses `m_(1)` and `m_(2)` connected by a light spring of natural length `l_(0)` is compressed completely and tied by a string. This system while moving with a velocity `v_(0)` along `+ve x`-axis pass through the origin at `t=0`. At this position the string snaps. Postion of mass `m_(1)` at time `t` is given by the equation. `x_(1) (t)=v_(0)t-A(1-cosomegat)` calculate :
(a) Position of the particle `m_(2)` as a function of time.
(b) `l_(0)` in terms of `A`.

Please log in or register to answer this question.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...