Correct Answer - A
Here, m=10kg
The resultant force acting on the body is
Let the resultant force F makes an angle `theta` w.r.t. 8N force,
From figure, `tan theta =(6)/(8)(N)/(N)=(3)/(4)`
The resultant acceleration of the body is, `a=(F)/(m)=(10)/(10)(N)/(kg)=1ms^(-2)`
The resultant acceleration, is along the direction of the resultant force. Hence, the resultant acceleration of the body is `1m s^(-2)` at an angle `tan ^(-1) ((3)/(4))` w.r.t. 8N force.